Obliczanie z 2 zapytań SQL - sql

Mam dwa pytania, które nie są pewne, jak je uruchomić, wykonując prostą matematykę.

SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31"

Zwraca: 7823

select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31"

Zwraca: 4106

Muszę zwrócić kwerendę: 4106/7823 X 100

Odpowiedzi:

Po prostu użyj tej składni:

SELECT (
CAST((<your first query>) as decimal)
/(<your second query>)
* 100
) AS Percents;

Twoje zapytanie powinno być

SELECT (
CAST((select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31") as decimal)
/(SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31")
* 100
) AS Percents;

Widzieć to pytanie SQLFiddle

Nie testowany kod, ale powinien to zrobić za Ciebie:

SELECT (SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31") /
(select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31")
* 100

Alternatywą byłoby

DECLARE @int1 as int
DECLARE @int2 as int
SET @int1 = (SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31")
SET @int2 = (select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31")
SELECT @int1/@int2 X 100