En scala "s immutable.Queue, hay dos metodos ambos nombrados enqueue:
/** Creates a new queue with element added at the end
* of the old queue.
*
* @param elem the element to insert
*/
def enqueue[B >: A](elem: B) = new Queue(elem :: in, out)
/** Returns a new queue with all elements provided by an `Iterable` object
* added at the end of the queue.
*
* The elements are prepended in the order they are given out by the
* iterator.
*
* @param iter an iterable object
*/
def enqueue[B >: A](iter: Iterable[B]) =
new Queue(iter.toList reverse_::: in, out)
No sé cómo resolver la ambigüedad y llamar al segundo. Esto es lo que he intentado:
Welcome to Scala version 2.10.0 (Java HotSpot(TM) 64-Bit Server VM, Java 1.7.0_07).
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scala> import collection.immutable.Queue
import collection.immutable.Queue
scala> val q: Queue[Int] = Queue(1,2,3)
q: scala.collection.immutable.Queue[Int] = Queue(1, 2, 3)
scala> q.enqueue(Iterable(4))
res0: scala.collection.immutable.Queue[Any] = Queue(1, 2, 3, List(4))
scala> q.enqueue[Int](Iterable(4))
<console>:10: error: overloaded method value enqueue with alternatives:
(iter: scala.collection.immutable.Iterable[Int])scala.collection.immutable.Queue[Int] <and>
(elem: Int)scala.collection.immutable.Queue[Int]
cannot be applied to (Iterable[Int])
q.enqueue[Int](Iterable(4))
^
Respuestas
8 para la respuesta № 1¡Difícil, complicado!
yo creó un boleto acerca de eso Usted ve, ha sido engañado por los tipos!
scala> q.enqueue(scala.collection.Iterable(4))
res8: scala.collection.immutable.Queue[Any] = Queue(1, 2, 3, List(4))
scala> q.enqueue(scala.collection.immutable.Iterable(4))
res9: scala.collection.immutable.Queue[Int] = Queue(1, 2, 3, 4)
los Iterable importado por defecto es el scala.collection.Iterable, que puede ser mutable o inmutable, pero la cola inmutable requiere la inmutable Iterable en lugar.