Calcolo da 2 query SQL - sql

Ho due domande che non sono sicuro di come eseguire una semplice matematica.

SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31"

Resi: 7823

select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31"

Resi: 4106

Devo restituire la query: 4106/7823 X 100

risposte:

1 per risposta № 1

Basta usare questa sintassi:

SELECT (
CAST((<your first query>) as decimal)
/(<your second query>)
* 100
) AS Percents;

Quindi la tua domanda dovrebbe essere

SELECT (
CAST((select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31") as decimal)
/(SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31")
* 100
) AS Percents;

Vedere questo SQLFiddle


1 per risposta № 2

Codice non testato ma questo dovrebbe farlo per voi:

SELECT (SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31") /
(select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31")
* 100

Un Alternato sarebbe

DECLARE @int1 as int
DECLARE @int2 as int
SET @int1 = (SELECT count(*) FROM CUSTOMERINFO
where member between "2013-01-01" and "2013-12-31")
SET @int2 = (select COUNT(DISTINCT ORDERINFO.OrderID) from orderinfo, orderiteminfo
where code = "810samp"
AND ORDERINFO.OrderID = ORDERITEMINFO.OrderID
AND orderinfo.PrepareDate between "2013-01-01" and "2013-12-31")
SELECT @int1/@int2 X 100