moja sql súčet hodnôt - mysql

Select Count(Case When an_user_plan.campaign_pid != 0 Then 1 End) As Email,
Count(Case When an_user_plan.sms_pid != 0 Then 1 End) As Sms,
Count(Case When an_user_plan.survey_pid != 0 Then 1 End) As Survey,
sum(Email,Sms,Survey)as total
From an_user_plan

toto sum(Email,Sms,Survey)as total majú chybu, ako súčet troch hodnôt Chcem celkom ako pridanie troch grófov vlaues ako to urobiť Prosím, pomôžte mi

odpovede:

SELECT SUM(campaign_pid != 0 +
sms_pid != 0 +
survey_pid != 0) AS total, ...

Skúste to:

Select Count(Case When an_user_plan.campaign_pid != 0 Then 1 End) +
Count(Case When an_user_plan.sms_pid != 0 Then 1 End) +
Count(Case When an_user_plan.survey_pid != 0 Then 1 End) as total
From an_user_plan

Hoci nemáte klauzulu GROUP BY, môžete použiť premenné -

SELECT @c1:=Count(...), @c2:=Count(...), @c1 + @c2 FROM table

V opačnom prípade môžete použiť poddotaz -

SELECT c1, c2, c1 + c2 FROM (
SELECT Count(...) c1, Count(...) c2 FROM table) t