Sir / Mam,
Korzystam z Oracle 11g. Mam tabelę o nazwie "Timeduration". Zawiera czas określony w godzinach i minutach. Chcę uzyskać całkowity czas w godzinach i minutach.
Timeduration
05:37
06:40
03:45
02:50
07:58
Chcę całkowity czas jako 25:30. Jak mogę napisać kod dla tego? Proszę pomóż mi."
Odpowiedzi:
1 dla odpowiedzi № 1with t as (
select "05:37" as timeduration from dual union all
select "06:40" as timeduration from dual union all
select "03:45" as timeduration from dual union all
select "02:50" as timeduration from dual union all
select "07:58" as timeduration from dual
),
d as (
select
--
-- 4 Converting the sum obtained in (3) into
-- an interval
numtodsinterval(
--
-- 3 Summing the day fractions obtained in (2)
sum(
--
-- 1 Convert the string "HH:MM" to a real date.
--
-- For example 05:37 becomes January 1st 0001 5:37
to_date("00010101" || t.timeduration, "yyyymmddhh24:mi")
--
-- 2 Subtract January 1st 0001 from that date
--
-- The result is a number of a day"s length
-- [1: 24 hours, 0.3: 8 hours etc)
- date "0001-01-01"),
--
"DAY"
) interval
from
t
)
select
(
-- 5 How many days are in the interval. Each day
-- corresponds to 24 hours:
extract (day from d.interval) * 24 +
--
-- 6 The hours «below» 24 hours must be added
-- seperatly:
extract (hour from d.interval)
)
--
-- 7 Hours are now extracted. Append the delimiter
|| ":" ||
(
--
-- 8 Finally: get the minutes from the interval
extract (minute from d.interval)
)
result
from d;